quant questions
Question
Q.no.-(1) The HCF of how many distinct pair of factors 18000is 75
solved
0
Quantitative Ability
2 years
1 Answer
1776 views
0
Answer ( 1 )
How to start
18000=2^4*3^2*5^3
*(5*3*4 = 60 Factors)*
75=5^2*3
Understanding the question
So ultimately we want to know how many factors of 18000/75 are co prime
I.e. 2^4*3*5 = 240
Number of factors of 240= 5*2*2 = 20
Now 1 is coprime with all factors
60-20+1 = 41 unordered pairs
82 ordered pairs