• Scholarship of Rs. 1250/- per month for class XI to XII.
• Scholarship of Rs. 2000/- per month for undergraduates and postgraduates.

Generally, state level exam takes place in the month of November every year and notification come out in the month of September. The next level exam takes place in the month of May every year.

All students of Class X studying in recognized schools are eligible to appear for the Stage-I examination. There will be no domicile restriction.

The examination will comprise these parts namely

• Mental Ability Test (MAT)
• Language Test (LT)
• Scholastic Ability Test (SAT)

For the preparation of such a prestigious exam, Team of Kailasha Foundation will bring a series of quizzes. In NTSE quiz series, this is the 11th quiz of Mental Ability Test of Positions and Direction under the head MAT in NTSE.

Attempt the quiz and find out your score.

Note: In this quiz, for every right answer you will be awarded 4 marks and for every wrong answer minus one mark will be awarded.

Click Here To Start Your Quiz

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• Scholarship of Rs. 1250/- per month for class XI to XII.
• Scholarship of Rs. 2000/- per month for undergraduates and postgraduates.

Generally, state level exam takes place in the month of November every year and notification come out in the month of September. The next level exam takes place in the month of May every year.

All students of Class X studying in recognized schools are eligible to appear for the Stage-I examination. There will be no domicile restriction.

The examination will comprise these parts namely

• Mental Ability Test (MAT)
• Language Test (LT)
• Scholastic Ability Test (SAT)

For the preparation of such a prestigious exam, Team of Kailasha Foundation will bring a series of quizzes. In NTSE quiz series, this is the 15th quiz of Mental Ability Test of Venn Diagrams under the head MAT in NTSE.

Attempt the quiz and find out your score.

Note: In this quiz, for every right answer you will be awarded 4 marks and for every wrong answer minus one mark will be awarded.

Click Here To Start Your Quiz

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Click here for more NTSE Quizzes

The post NTSE MAT – Venn Diagrams – 15 question in 10 minute appeared first on Kailasha Foundation.

• Scholarship of Rs. 1250/- per month for class XI to XII.
• Scholarship of Rs. 2000/- per month for undergraduates and postgraduates.

Generally, state level exam takes place in the month of November every year and notification come out in the month of September. The next level exam takes place in the month of May every year.

All students of Class X studying in recognized schools are eligible to appear for the Stage-I examination. There will be no domicile restriction.

The examination will comprise these parts namely

• Mental Ability Test (MAT)
• Language Test (LT)
• Scholastic Ability Test (SAT)

For the preparation of such a prestigious exam, Team of Kailasha Foundation will bring a series of quizzes. In NTSE quiz series, this is the 13th quiz of Mental Ability Test of Dices and Cubes under the head MAT in NTSE.

Attempt the quiz and find out your score.

Note: In this quiz, for every right answer you will be awarded 4 marks and for every wrong answer minus one mark will be awarded.

Click Here To Start Your Quiz

Kailasha Foundation – Bringing Solutions To You

Follow us on Facebook, Twitter, Instagram, LinkedIn for regular updates.

Click here for more NTSE Quizzes

The post NTSE MAT – Dices and Cubes – 15 Questions in 15 Min appeared first on Kailasha Foundation.

• Scholarship of Rs. 1250/- per month for class XI to XII.
• Scholarship of Rs. 2000/- per month for undergraduates and postgraduates.

Generally, state level exam takes place in the month of November every year and notification come out in the month of September. The next level exam takes place in the month of May every year.

All students of Class X studying in recognized schools are eligible to appear for the Stage-I examination. There will be no domicile restriction.

The examination will comprise these parts namely

• Mental Ability Test (MAT)
• Language Test (LT)
• Scholastic Ability Test (SAT)

For the preparation of such a prestigious exam, Team of Kailasha Foundation will bring a series of quizzes. In NTSE quiz series, this is the 11th quiz of Mental Ability Test of Positions and Direction under the head MAT in NTSE.

Attempt the quiz and find out your score.

Note: In this quiz, for every right answer you will be awarded 4 marks and for every wrong answer minus one mark will be awarded.

Click Here To Start Your Quiz

Kailasha Foundation – Bringing Solutions To You

Follow us on Facebook, Twitter, Instagram, LinkedIn for regular updates.

Click here for more NTSE Quizzes

The post NTSE MAT – Directions and Positions – 15 Questions in 15 Min appeared first on Kailasha Foundation.

Average=(sum / N) where N is total number of objects

Weighted Average: The average between two sets of numbers is closer to the set with more numbers.
If the value of each item is increased by x, then the average of the group will also increase by x.

If the value of each item is decreased by y, then the average of the group of items will also decrease by y.
If the value of each item is multiplied by the same value m, then the average of the group or items will also get multiplied by m.
If the value of each item is multiplied by the same value n, then the average of the group or items will also get divided by n.
If we know only the average of the two groups individually, we cannot find out the average of the combined group of items.

Average of x natural no’s = (x+1)/2

Average of even No’s = (x+1)

Average of odd No’s = x

 Change in the value of a Quantity and its effect on the Average

When one/more than one quantity is not removed but replaced with same no. of quantities of different value,

Change in the no. of quantities and its effect on Average

+ = if quantities are Added, – = if quantities are removed

Time and Work

If a person ‘X’ can complete a piece of work in ‘Y’ days, then

Work Done by X in 1 day = 1/Y

If Utkarsh can complete a piece of work in ‘X’ days and Prashant can complete a piece of work in ‘Y’ days, then

Work done by Utkarsh and Prashant together in 1 day = X+Y/XY

Trick 1: If Adarsh can do a work in D1 days and Bhanu can do the same work in D2 days then Adarsh and Bhanu together can do the same work in (D1 x D2)/ (D1 + D2)

Trick 2: Sometimes the work done is dependent on the number of days worked and efficiency of each worker. Let’s see how the formula changes in this case:

• If person P1 can do the work in D1 days and M2 persons can do the same work in D2 days then we can say M1.D1 = M2.D2
• If the persons work T1 and T2 hours per day respectively then the equation gets modified to M1.D1.T1 = M2.D2.T2
• If the persons has efficiency of E1 and E2 respectively then: M1.D1.T1.E1 = M2.D2.T2.E2

Pipes & Cisterns

Trick: If a pipe A can fill a tank in ‘x’ hours and Pipe B can fill a tank in ‘y’ hours, then

Time Taken by both the pipes to fill the tank together = xy/(x+y)

Time, Speed and Distance

Trick 1: Speed = Distance/ Time and the unit of Speed is Km/hr or m/s

Trick 2: If an object covers a certain distance with a speed of ‘p’ Km/hr and again covers the same distance with a speed of ‘q’ Km/hr, then

Average Speed for the Entire Journey = 2 pq/(p+q)

Boats and Streams

Trick: If the speed of stream is ‘p’ Km/hr and the speed of boat in still water is ‘q’ Km/hr, then

Speed of Boat Downstream = (p + q) Km/hr

Speed of Boat Upstream = (q – p) Km/hr

Mixtures and Alligations

Trick 1: When two different commodities are mixed such that one is cheaper than the other, then:

Here Mean Price is CP of mixture per unit quantity.

Trick 2: When x amount of commodity 1 is replaced with commodity 2 of y quantity n times, then:

Quadratic Equations

ax2 + bx + c = 0.

py2 + qy + c = 0

Trick 1:

Sum of roots = -b/a

Product of roots = c/a

Trick 2: A quadratic equation ax2 + bx + c = 0 will have reciprocal roots when a = c

Approximation

Trick 1: Use the BODMAS rule to solve the simplification questions. This is the basis of simplification questions.

Trick 2: Round of decimal numbers to the nearest whole numbers to get the approximate value of the equation.

Ratio Proportion

Ratio is a fraction of two values. It can be represented in any of the following ways:

=> x/y,   x : y , x÷y

• In ratio of the form x : y,  x is called as the antecedent/first term and y is the consequent/second term.
• Generally, ratio is a handy way to compare two terms.
• For example : 4 / π > 1 , it is clear that 4 > π
• One thing that has to be remembered while comparing two numbers in a ratio is that they should be represented in same units. For example, if x is in meters and y in litres they cannot be compared by using ratio as they are expressed in different units – meters vs litres.

A proportion is the equality of two ratios/ fractions.

• If x : y = a : b, it can be written as  x : y :: a : b and it is said that x, y, a, b are in proportion.
• Here x and b are called extremes, while y and a are called mean terms.
• Product of means=Product of extremes
  Thus,
  x :y :: a : b  => (y∗a)=(x∗b)
• If x : y=a : b

b is called the fourth proportional to x, y and a.
a is called the third proportional to x and y.

• Sub-duplicate: Sub-duplicate ratio of (a:b) is (a^1/2: b^1/2)
• Duplicate ratio of (a:b) is (a^2:b^2)
• Triplicate Ratio:Triplicate ratio of (a:b) is (a^3:b^3)
• Sub-triplicate Ratio: Sub-triplicate ratio of (a:b) is (a^1/3:b^1/3)
• If a/b=c/d then, a+b/a−b=c+d/c−d This is known as Componendo and Dividendo.
• We say that x is directly proportional to y, if x=ky for some constant k and we write, x∝y
• We say that x is inversely proportional to y, if xy=k for some constant k and we write, x∝1y

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To express x% as a fraction, divide it by 100 ⇒ x% = x/100

To express a fraction as %, multiply it by 100 ⇒ x/y = [(x/y) × 100] %

x% of y is given by (y × x/100 )

If X’s age is a% more than Y’s age, the Y’s age is less than X’s age by [ a / (100+a)] * 100%

If ‘M’ is x% of ‘N’ and ‘P’ is y% of ‘N’ then ‘M’ is (x/y) * 100% of ‘P’.

If the sides of the triangle, rectangle, square, circle, rhombus etc is

• Increased by a%. Its area is increased by2a+(a²/100)
• If decreased b%. Its areas is decreased by,-2b+(b²/100)

The students in a school are ‘P’. It increased by x% during the 1^st year, increased by y% during 2^nd year and again increased by z% during 3^rd year. The students in school after 3 years will be,

P *[(100+x)/100] * [(100+y)/100] * [(100+z)/100]

 Problem on Ages

1. If the current age is x, then n times the age is nx.
2. If the current age is x, then age n years later/hence = x + n.
3. If the current age is x, then age n years ago = x – n.
4. The ages in a ratio a:b ill be ax and bx.
5. If current age is x, then 1/n of the age is x/n.

 If the present age of Sharma Jee is ‘x’ years, then

‘n’ years hence, Age of Sharma Jee would be = (x + n) years

‘n’ years ago, Age of Sharma Jee would be = (x – n) years

Super Tip: You don’t need to always start forming equations from where the question starts.

Number Series

The only difficult part about solving questions on number and alphabet series is determining the pattern. Once you practice 40-50 questions on this topic, you will be aware of 90% of the possible pattern. A shortcut is to read the tricks on solving series questions. Some of them are highlighted here:

Trick 1: Calculate the difference between the immediate or alternate numbers and observe the pattern in the differences.

Trick 2: Observe the sequence for Prime Number series

Trick 3: Observe the sequence for Geometric series, Perfect Squares/Cubes.

Profit & Loss

Cost Price-The price at which an article is purchased is known as cost price (C.P.)

Selling Price-The price at which the article is sold is known as selling price (S.P.)
Profit = SP-CP (SP>CP)
Loss = CP-SP (CP>SP)

Profit % = (Profit x 100)/CP
Loss% = [(CP – SP)/CP] x 100
CP= {100 /(100+profit%)} x SP
CP={100/(100-loss%)} x SP

S.P. = C.P. x [(100 + profit%) / 100]

S.P. = C.P. x [(100 – loss%) / 100]

If there is a Profit of x% and loss of y % in a transaction, then the resultant profit or loss% is given by [x – y – (x × y/100)]

Note- For profit use sign + in previous formula and for loss use – sign. If resultant is positive then overall its profit. However, if it is negative then overall we have a loss.

If a cost price of m articles is equal to the selling Price of n articles,

(C.P of m article = S.P. of n article) then Profit percentage

(m – n)/n×100%

If m parts are sold at x% profit, n parts are sold at y % profit and p parts are sold at z% profit Rs. ‘R’ is earned as overall profit than the value of total consignment
 R ×100 / (mx +ny +pz)

Ankit purchases a certain no. of the article at m  rupee and the same no. at n a rupee. He mixes them together and sells them at p a rupee then his gain or loss

[{2mn/(m+n)p} -1]× 100

Marked price = Cost price + Markup

Always Remember: Markup is an extra price on Cost Price. So, Markup is always calculated on CP

%Markup = [Markup/CP]*100

Discount (if SP < MP) = MP – SP i.e. SP = MP – Discount

Always Remember: Discount is deducted from Marked Price. So, Discount is always calculated on MP and

%Discount = [Discount/MP]*100

Trick 1: If most of the information given in the form of percentages in the question, start by assuming CP = 100.

Trick 2:  Discount is usually given on marked price. Hence, in this case, marked price will be higher than the final selling price.

Simple and Compound Interest

Principal: – The money borrowed or lent out for certain period is called the principal or the Sum.

Interest: – Extra money paid for using other money is called interest

The cost of borrowing money is defined as Simple Interest. It is of two types – simple interest or compound interest. Simple interest (SI) is calculated only on the principal (P) whereas Compound interest (CI) is calculated on the principal and also on the accumulated interest of previous periods i.e. “interest on interest.” This compounding effect makes a big difference in the amount of interest payable on the principal.

Simple interest is:

Simple Interest = Principal x Interest Rate x Term of the loan (Time of Loan)

SI = P x i x n/100 when the interest rate is taken in percent.

Compound Interest

CI = P [(1 + i)ⁿ – 1]

where P = Principal, i = annual interest rate in percentage terms, and n = number of compounding periods.

Compounding periods: When calculating compound interest, the number of compounding periods makes a significant difference. The basic rule is that the higher the number of compounding periods, the greater the amount of compound interest. So for every INR 100 principal over a certain period of time, the amount of interest accrued at 10% annually will be lower than interest accrued at 5% semi-annually, which will, in turn, be lower than interest accrued at 2.5% quarterly.

In the formula for calculating compound interest, the variables “i” and “n” have to be adjusted if the number of compounding periods is more than once a year. That is, “i” has to be divided by the number of compounding periods per year, and “n” has to be multiplied by the number of compounding periods. Therefore, for a 10-year loan at 10%, where interest is compounded semi-annually (number of compounding periods = 2), i = 5% (i.e. 10% / 2) and n = 20 (i.e. 10 x 2).

The following table demonstrates the difference that the number of compounding periods can make over time for an INR 10,000 loan taken for a 10-year period.

Shortcut Trick: Rule of 72 

The Rule of 72 calculates the approximate time over which an investment will double at a given rate of return or interest “i”, and is given by (72 / i). It can only be used for annual compounding.

For example, an investment that has a 6% annual rate of return will double in 12 years. An investment with an 9% rate of return will double in 8 years.

Trick 1: Formula for calculating simple interest is simple.

S.I. = PTR/100

What if the rate is R1, R2 and R3 in the 1st, 2nd and 3rd year. In this case, the amount after 3 years would be:

A = P (1 +R1/100) (1 + R2/100) (1 + R3/100)

Trick 2: Formula for calculating compound interest is a little more complex.

A = P [1+ r/100]t

This formula applies when interest is compounded annually.

When interest is compounded half yearly, rate = 2r

compounded quarterly, rate = 4r

compounded monthly, rate = 12r

Trick 3: When the rate of interest is not equal every year:

A = P [1+ r1/100]t1 [1+ r2/100]t2 …. and so on

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• Learn tables up to 25
• Learn squares up to 25

• Learn cubes up to 15

• Learn fractions up to 1/20 to ease your calculations in the exam.

1 = 100%
1 /2= 50%
1 /3= 33.33%
1/4 = 25%
1/5 = 20%
1 /6= 16.66%
1/7 = 14.28%
1/8 = 12.5%
1/9 = 11.11%
1/10 = 10%
1/11 = 9.09%
1/12 = 8.33%
1/13 = 7.69%
1/14 = 7.14%

1/15 = 6.66%

1/16 = 6.25%

1/17 = 5.88%

1/18 = 5.55%

1/19 = 5.26%

1/20 = 5%

Remember the DIVISIBILITY RULES

• 2- if the last digit of  is 2, 4, 6, 8, or 0;
• 3- if the sum of digits is a multiple of 3;
• 4-  if the last 2 digits are a multiple of 4;
• 5- if the last digit of  is either 0 or 5;
• 6-  if  is divisible by both 2 and 3;
• 7- if subtracting twice the last digit from the numbers made by remaining digits gives a multiple of 7 
  (e.g. 658 is divisible by 7 because 65- 2*8 = 65 -16 = 49 , which is a multiple of 7);
• 8- if the last 3 digits are a multiple of 8;
• 9- if the sum of digits is a multiple of 9;
• 10- if the last digit of  is 0;
• 11- if the difference of the alternating sum of digits of  is a multiple of 11 
  (e.g. 2343 is divisible by 11 because 2-3+4-3 = 0 which is a multiple of 11);
• 12- if divisible by both 3 and 4.
• 13- if its unit’s place digit is multiplied by 4 and added to the remaining digits and the number obtained is divisible by 13
• 14- if the number is divisible by both 2 and 7
• 15- if the number is divisible by both 3 and 5
• 16- if its last 4 digits is divisible by 16 or if the last four digits are zeros
• 17- if its unit’s place digit is multiplied by 5 and subtracted from the remaining digits and the number obtained is divisible by 17
• 18- if the number is divisible by both 2 and 9.
• 19- if its unit’s place digit is multiplied by 2 and added to the remaining digits and the number obtained is divisible by 19.

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